What is the derivative of f(x)=sqrt(x)+6\sqrt[3]{x} ?

The derivative of f(x)=sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}

What is the first derivative of f(x)=sqrt(x)+6\sqrt[3]{x} ?

The first derivative of f(x)=sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}

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Popular >

derivative of

\frac{1}{2 x} + \frac{2}{x ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (x) = \frac{1}{2 x}

= \frac{1}{2 x} + \frac{2}{x ^{\frac{2}{3}}}

\frac{d}{d x} (3 e^{x} + x e^{x})

\int e^{c o s (t)} sin (2 t) d t

\frac{6}{9 - x}

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What is the derivative of f(x)=sqrt(x)+6\sqrt[3]{x} ?
The derivative of f(x)=sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}
What is the first derivative of f(x)=sqrt(x)+6\sqrt[3]{x} ?
The first derivative of f(x)=sqrt(x)+6\sqrt[3]{x} is 1/(2sqrt(x))+2/(x^{2/3)}