What is the tangent of y= 4/(sqrt(x)),(49, 4/7) ?

The tangent of y= 4/(sqrt(x)),(49, 4/7) is y=-2/343 x+6/7

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tangent of y= 4/(sqrt(x)),(49, 4/7)

tangent of

y = \frac{4}{x}, (49, \frac{4}{7})

y = - \frac{2}{343} x + \frac{6}{7}

Solution steps

Find the slope of

y = \frac{4}{x} : \frac{d y}{d x} = - \frac{2}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{4}{x}

(49, \frac{4}{7}) : m = - \frac{2}{343}

Find the line with slope m=

- \frac{2}{343}

and passing through

(49, \frac{4}{7}) : y = - \frac{2}{343} x + \frac{6}{7}

y = - \frac{2}{343} x + \frac{6}{7}

\frac{\partial}{\partial v} (\frac{1}{3} (u + v))

\int (\frac{x}{6})^{6} d x

\frac{d}{d z} (4 - z)

\frac{d}{d x} (ln (\frac{x + 3}{x ^{2}}))

y^{^{''}} + 2 y^{^{'}} = sin (2 t)

What is the tangent of y= 4/(sqrt(x)),(49, 4/7) ?
The tangent of y= 4/(sqrt(x)),(49, 4/7) is y=-2/343 x+6/7