What is (\partial)/(\partial x)(5e^{yz}cos(xyz)) ?

The answer to (\partial)/(\partial x)(5e^{yz}cos(xyz)) is -5e^{yz}yzsin(yzx)

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(\partial)/(\partial x)(5e^{yz}cos(xyz))

\frac{\partial}{\partial x} (5 e^{yz} cos (x yz))

- 5 e^{yz} yz sin (yz x)

Solution steps

\frac{\partial}{\partial x} (5 e^{yz} cos (x yz))

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 e^{yz} \frac{\partial}{\partial x} (cos (x yz))

Apply the chain rule:

- sin (x yz) \frac{\partial}{\partial x} (x yz)

= - sin (x yz) \frac{\partial}{\partial x} (x yz)

\frac{\partial}{\partial x} (x yz) = yz

= 5 e^{yz} (- sin (x yz) yz)

Simplify

= - 5 e^{yz} yz sin (yz x)

x^{2} - 8 x + 15, 0

\frac{d}{d x} (2 x e^{- \frac{x ^{2}}{2}})

\frac{\partial}{\partial y} (y x)

f (x) = 6 x^{2} - 4 x + 4, (1, 6)

\frac{\partial}{\partial y} (4 - x^{2} - 8 y^{2})

What is (\partial)/(\partial x)(5e^{yz}cos(xyz)) ?
The answer to (\partial)/(\partial x)(5e^{yz}cos(xyz)) is -5e^{yz}yzsin(yzx)