What is (\partial)/(\partial x)(2x^2+4y^2+1) ?

The answer to (\partial)/(\partial x)(2x^2+4y^2+1) is 4x

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(\partial)/(\partial x)(2x^2+4y^2+1)

\frac{\partial}{\partial x} (2 x^{2} + 4 y^{2} + 1)

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + 4 y^{2} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (4 y^{2}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (4 y^{2}) = 0

\frac{\partial}{\partial x} (1) = 0

= 4 x + 0 + 0

Simplify

= 4 x

\frac{d}{d x} (2^{x^{3} + 3 x})

tan (t) y^{^{'}} - y = 1

\int x^{2} x^{2} - 9 d x

\int \frac{2 x + 3}{2 - x} d x

\int x (a^{2} - x^{2})^{\frac{3}{2}} d x

What is (\partial)/(\partial x)(2x^2+4y^2+1) ?
The answer to (\partial)/(\partial x)(2x^2+4y^2+1) is 4x