en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-10y^'+9y=0

Solution

y^{^{''}} - 10 y^{^{'}} + 9 y = 0

Solution

y = c_{1} e^{9 t} + c_{2} e^{t}

Solution steps

y^{''} (t) - 10 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} e^{9 t} + c_{2} e^{t}

y = c_{1} e^{9 t} + c_{2} e^{t}

Popular Examples

tangent of y=x^4+4x^2-x,(1,4)tangent of

y = x^{4} + 4 x^{2} - x, (1, 4)

tangent of y= 1/3 x^3-3x^2+5x tangent of

y = \frac{1}{3} x^{3} - 3 x^{2} + 5 x

integral of x*\sqrt[3]{x-4}

derivative of (x^2-1)/(x^2)derivative of

\frac{x ^{2} - 1}{x ^{2}}

limit as x approaches 0 of ((4+x)^{-1}-4^{-1})/x

x \to 0 lim (\frac{( 4 + x ) ^{- 1} - 4 ^{- 1}}{x})

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-10y^'+9y=0 ?
The solution for y^{''}-10y^'+9y=0 is y=c_{1}e^{9t}+c_{2}e^t