What is the solution for y^{''}-6y^'+5y=0,y(0)=3,y^'(0)=11 ?

The solution for y^{''}-6y^'+5y=0,y(0)=3,y^'(0)=11 is y=2e^{5t}+e^t

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y^{''}-6y^'+5y=0,y(0)=3,y^'(0)=11

y^{^{''}} - 6 y^{^{'}} + 5 y = 0, y (0) = 3, y^{^{'}} (0) = 11

y = 2 e^{5 t} + e^{t}

Solution steps

y^{''} (t) - 6 y^{'} (t) + 5 y = 0

Solve linear ODE:

y = 2 e^{5 t} + e^{t}

y = 2 e^{5 t} + e^{t}

x \to - 3 lim (\frac{5 x ^{2} + 15 x}{x + 3})

x \to π lim (ln ∣ cos (x) - 4 ∣)

\int (\frac{( 7 - 2 x )}{x ^{\frac{1}{2}}} + 3 (5 - e^{x} + 2 e^{3})) d x

x^{3} e^{x}

\int (1 - x) cos (2 x) d x

What is the solution for y^{''}-6y^'+5y=0,y(0)=3,y^'(0)=11 ?
The solution for y^{''}-6y^'+5y=0,y(0)=3,y^'(0)=11 is y=2e^{5t}+e^t