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Popular >

y^'-5y=-t

Solution

y^{^{'}} - 5 y = - t

Solution

y = \frac{5 t + 1}{25} + c_{1} e^{5 t}

Solution steps

y^{'} (t) - 5 y = - t

Solve linear ODE:

y = \frac{5 t + 1}{25} + c_{1} e^{5 t}

y = \frac{5 t + 1}{25} + c_{1} e^{5 t}

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Frequently Asked Questions (FAQ)

What is the solution for y^'-5y=-t ?
The solution for y^'-5y=-t is y=(5t+1)/(25)+c_{1}e^{5t}