What is the derivative of f(x)=-8.25x^2+66x ?

The derivative of f(x)=-8.25x^2+66x is -16.5x+66

What is the first derivative of f(x)=-8.25x^2+66x ?

The first derivative of f(x)=-8.25x^2+66x is -16.5x+66

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derivative of

f (x) = - 8.25 x^{2} + 66 x

- 16.5 x + 66

Solution steps

\frac{d}{d x} (- 8.25 x^{2} + 66 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (8.25 x^{2}) + \frac{d}{d x} (66 x)

\frac{d}{d x} (8.25 x^{2}) = 16.5 x

\frac{d}{d x} (66 x) = 66

= - 16.5 x + 66

\frac{s - 1}{s ^{2} ( s + 3 )}

t \to a lim (t)

x^{2} - 2 x

\frac{\partial}{\partial y} (\frac{7 y}{x})

7 x^{2} - 8 x + 3

What is the derivative of f(x)=-8.25x^2+66x ?
The derivative of f(x)=-8.25x^2+66x is -16.5x+66
What is the first derivative of f(x)=-8.25x^2+66x ?
The first derivative of f(x)=-8.25x^2+66x is -16.5x+66