What is the derivative of asin(bx) ?

The derivative of asin(bx) is acos(bx)b

What is the first derivative of asin(bx) ?

The first derivative of asin(bx) is acos(bx)b

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\frac{d}{d x} (a sin (b x))

a cos (b x) b

Solution steps

\frac{d}{d x} (a sin (b x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d x} (sin (b x))

Apply the chain rule:

cos (b x) \frac{d}{d x} (b x)

= cos (b x) \frac{d}{d x} (b x)

\frac{d}{d x} (b x) = b

= a cos (b x) b

\frac{d}{d x} (\frac{x}{1 - ln ( x - 7 )})

\int \frac{1}{x cos ( ln ( x ) )} d x

x \to - 2 + lim (\frac{x ^{2}}{x + 2})

\frac{\partial}{\partial x} (x (20 - 2 x) (16 - 2 x))

\frac{\partial}{\partial x} (x^{9} y^{9} - x^{8} y^{8})

What is the derivative of asin(bx) ?
The derivative of asin(bx) is acos(bx)b
What is the first derivative of asin(bx) ?
The first derivative of asin(bx) is acos(bx)b