What is the derivative of x^3-6x^2+9x+4 ?

The derivative of x^3-6x^2+9x+4 is 3x^2-12x+9

What is the first derivative of x^3-6x^2+9x+4 ?

The first derivative of x^3-6x^2+9x+4 is 3x^2-12x+9

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\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x + 4)

3 x^{2} - 12 x + 9

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} + 9 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (9 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (4) = 0

= 3 x^{2} - 12 x + 9 + 0

Simplify

= 3 x^{2} - 12 x + 9

\int_{0}^{5} \frac{1}{u ^{2} - 25} d u

y = 4 cos (x), (\frac{π}{3}, 2)

- x^{- 2} e^{\frac{1}{x}}

5 + 4 x^{2} - 2 x^{3}

What is the derivative of x^3-6x^2+9x+4 ?
The derivative of x^3-6x^2+9x+4 is 3x^2-12x+9
What is the first derivative of x^3-6x^2+9x+4 ?
The first derivative of x^3-6x^2+9x+4 is 3x^2-12x+9