What is the derivative of x/8-8/x ?

The derivative of x/8-8/x is 1/8+8/(x^2)

What is the first derivative of x/8-8/x ?

The first derivative of x/8-8/x is 1/8+8/(x^2)

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derivative of

\frac{x}{8} - \frac{8}{x}

\frac{1}{8} + \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{8} - \frac{8}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{8}) - \frac{d}{d x} (\frac{8}{x})

\frac{d}{d x} (\frac{x}{8}) = \frac{1}{8}

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

= \frac{1}{8} - (- \frac{8}{x ^{2}})

Simplify

= \frac{1}{8} + \frac{8}{x ^{2}}

y^{^{''}} - 7 y^{^{'}} + 6 y = 0

\int \frac{y ^{3}}{y ^{2} + 1} d y

\frac{d}{d x} (a x cos (3 x) + b x sin (3 x))

\int \frac{2}{t ^{2}} d t

\int (x^{3} - sin (x)) d x

What is the derivative of x/8-8/x ?
The derivative of x/8-8/x is 1/8+8/(x^2)
What is the first derivative of x/8-8/x ?
The first derivative of x/8-8/x is 1/8+8/(x^2)