What is the derivative of f(x)=x^2-3x+1 ?

The derivative of f(x)=x^2-3x+1 is 2x-3

What is the first derivative of f(x)=x^2-3x+1 ?

The first derivative of f(x)=x^2-3x+1 is 2x-3

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derivative of

f (x) = x^{2} - 3 x + 1

2 x - 3

Solution steps

\frac{d}{d x} (x^{2} - 3 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 2 x - 3 + 0

Simplify

= 2 x - 3

\frac{d}{d x} (lo g_{x} (e))

\int_{1}^{x} \frac{1}{t ^{3} + 1} d t

\frac{d}{d t} ((t + 1)^{\frac{2}{3}} (2 t^{2} - 1)^{3})

\int (\frac{x + 6}{x ^{2} + 11 x + 18}) d x

\frac{d}{d x} (x^{6} + 3 x^{4} + 7 x^{2})

What is the derivative of f(x)=x^2-3x+1 ?
The derivative of f(x)=x^2-3x+1 is 2x-3
What is the first derivative of f(x)=x^2-3x+1 ?
The first derivative of f(x)=x^2-3x+1 is 2x-3