What is the solution for 2ydx+(y-2x)dy=0 ?

The solution for 2ydx+(y-2x)dy=0 is y=-(2x)/(\W(-\frac{2x){c_{1}})}

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2ydx+(y-2x)dy=0

2 y d x + (y - 2 x) d y = 0

y = - \frac{2 x}{W ( - \frac{2 x}{c _{1}} )}

Solution steps

2 y d x + (y - 2 x) d y = 0

Solve using substitution:

y = - \frac{2 x}{W ( - \frac{2 x}{c _{1}} )}

y = - \frac{2 x}{W ( - \frac{2 x}{c _{1}} )}

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What is the solution for 2ydx+(y-2x)dy=0 ?
The solution for 2ydx+(y-2x)dy=0 is y=-(2x)/(\W(-\frac{2x){c_{1}})}