What is (d^4)/(dx^4)(19e^{x^2}) ?

The answer to (d^4)/(dx^4)(19e^{x^2}) is 38(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})

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(d^4)/(dx^4)(19e^{x^2})

\frac{d ^{4}}{d x ^{4}} (19 e^{x^{2}})

38 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

Solution steps

\frac{d ^{4}}{d x ^{4}} (19 e^{x^{2}})

\frac{d}{d x} (19 e^{x^{2}}) = 38 e^{x^{2}} x

= \frac{d ^{3}}{d x ^{3}} (38 e^{x^{2}} x)

\frac{d}{d x} (38 e^{x^{2}} x) = 38 (2 e^{x^{2}} x^{2} + e^{x^{2}})

= \frac{d ^{2}}{d x ^{2}} (38 (2 e^{x^{2}} x^{2} + e^{x^{2}}))

\frac{d}{d x} (38 (2 e^{x^{2}} x^{2} + e^{x^{2}})) = 38 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)

= \frac{d}{d x} (38 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x))

\frac{d}{d x} (38 (4 e^{x^{2}} x^{3} + 6 e^{x^{2}} x)) = 38 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

= 38 (8 e^{x^{2}} x^{4} + 24 e^{x^{2}} x^{2} + 6 e^{x^{2}})

\frac{d}{d x} (x a^{2} - x^{2})

\int \frac{1}{- x ^{2} - 10 x - 24} d x

x \to 3 lim (1 - x - x^{2})

\frac{d}{d x} (\frac{1}{2 x} + \frac{1}{9 x ^{\frac{8}{9}}})

\int_{1}^{2} \frac{x - 1}{x} d x

What is (d^4)/(dx^4)(19e^{x^2}) ?
The answer to (d^4)/(dx^4)(19e^{x^2}) is 38(8e^{x^2}x^4+24e^{x^2}x^2+6e^{x^2})