What is the derivative of x7^x ?

The derivative of x7^x is 7^x+ln(7)*7^xx

What is the first derivative of x7^x ?

The first derivative of x7^x is 7^x+ln(7)*7^xx

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derivative of

x 7^{x}

7^{x} + ln (7) \cdot 7^{x} x

Solution steps

\frac{d}{d x} (x \cdot 7^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = 7^{x}

= \frac{d x}{d x} 7^{x} + \frac{d}{d x} (7^{x}) x

\frac{d x}{d x} = 1

\frac{d}{d x} (7^{x}) = 7^{x} ln (7)

= 1 \cdot 7^{x} + 7^{x} ln (7) x

Simplify

= 7^{x} + ln (7) \cdot 7^{x} x

f (x) = 18 x^{3} - x

\frac{\partial}{\partial x} (5 tan (5 x))

\frac{d}{d x} (\frac{cos ( 2 x )}{sin ( 2 x )})

(x - 1) d y + (y - x^{- 2} + 2 x^{- 3}) d x = 0

\frac{\partial}{\partial x} (- 2 yz)

What is the derivative of x7^x ?
The derivative of x7^x is 7^x+ln(7)*7^xx
What is the first derivative of x7^x ?
The first derivative of x7^x is 7^x+ln(7)*7^xx