What is the solution for 4y-y^{''}=10e^{(-3x)} ?

The solution for 4y-y^{''}=10e^{(-3x)} is y=c_{1}e^{2x}+c_{2}e^{-2x}-2e^{-3x}

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4y-y^{''}=10e^{(-3x)}

4 y - y^{^{''}} = 10 e^{(- 3 x)}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 2 e^{- 3 x}

Solution steps

4 y - y^{''} (x) = 10 e^{(- 3 x)}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 2 e^{- 3 x}

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 2 e^{- 3 x}

e^{2 x + y} y^{^{'}} = e^{x - y}

\frac{d}{d x} (x^{5} - 5 x^{3})

\frac{e ^{x}}{x ^{2} + 3}

7 arctan (x + 1 + x^{2})

\frac{x}{7}

What is the solution for 4y-y^{''}=10e^{(-3x)} ?
The solution for 4y-y^{''}=10e^{(-3x)} is y=c_{1}e^{2x}+c_{2}e^{-2x}-2e^{-3x}