What is the derivative of 18sqrt(x)-3x ?

The derivative of 18sqrt(x)-3x is 9/(sqrt(x))-3

What is the first derivative of 18sqrt(x)-3x ?

The first derivative of 18sqrt(x)-3x is 9/(sqrt(x))-3

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derivative of

18 x - 3 x

\frac{9}{x} - 3

Solution steps

\frac{d}{d x} (18 x - 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (18 x) - \frac{d}{d x} (3 x)

\frac{d}{d x} (18 x) = \frac{9}{x}

\frac{d}{d x} (3 x) = 3

= \frac{9}{x} - 3

f (x) = - 1 - 9 x^{2}, at x = 3

r^{2} - x^{2}

x^{2}, 4

\int \frac{1}{x x + 6} d x

\int \frac{( x ^{a} - x ^{b} ) ^{2}}{x} d x

What is the derivative of 18sqrt(x)-3x ?
The derivative of 18sqrt(x)-3x is 9/(sqrt(x))-3
What is the first derivative of 18sqrt(x)-3x ?
The first derivative of 18sqrt(x)-3x is 9/(sqrt(x))-3