What is the limit as x approaches-1 of e^{(x-2)/(1+x)} ?

The limit as x approaches-1 of e^{(x-2)/(1+x)} is diverges

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limit as x approaches-1 of e^{(x-2)/(1+x)}

x \to - 1 lim (e^{\frac{x - 2}{1 + x}})

diverges

Solution steps

x \to - 1 lim (e^{\frac{x - 2}{1 + x}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (e^{\frac{x - 2}{1 + x}}) = 0

x \to - 1 - lim (e^{\frac{x - 2}{1 + x}}) = \infty

= diverges

\frac{\partial}{\partial x} (y^{\frac{y}{x}} sin (\frac{y}{x}))

(- 2.7) (4.3)

3 (y^{4} + 1) d x + 4 x y^{3} d y = 0

\frac{d y}{d x} = \frac{2 x y}{1 + x ^{2}}

\frac{2 x}{3}

What is the limit as x approaches-1 of e^{(x-2)/(1+x)} ?
The limit as x approaches-1 of e^{(x-2)/(1+x)} is diverges