What is the derivative of y=(x^2+6x+2)^3 ?

The derivative of y=(x^2+6x+2)^3 is 3(x^2+6x+2)^2(2x+6)

What is the first derivative of y=(x^2+6x+2)^3 ?

The first derivative of y=(x^2+6x+2)^3 is 3(x^2+6x+2)^2(2x+6)

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derivative of

y = (x^{2} + 6 x + 2)^{3}

3 (x^{2} + 6 x + 2)^{2} (2 x + 6)

Solution steps

\frac{d}{d x} ((x^{2} + 6 x + 2)^{3})

Apply the chain rule:

3 (x^{2} + 6 x + 2)^{2} \frac{d}{d x} (x^{2} + 6 x + 2)

= 3 (x^{2} + 6 x + 2)^{2} \frac{d}{d x} (x^{2} + 6 x + 2)

\frac{d}{d x} (x^{2} + 6 x + 2) = 2 x + 6

= 3 (x^{2} + 6 x + 2)^{2} (2 x + 6)

\int \frac{1}{v ^{2} + v} d v

(5 x - 2)^{2} (4 - x^{3})^{2}

f (x) = arctan (x)

\frac{\partial}{\partial x} ((x y)^{x y})

What is the derivative of y=(x^2+6x+2)^3 ?
The derivative of y=(x^2+6x+2)^3 is 3(x^2+6x+2)^2(2x+6)
What is the first derivative of y=(x^2+6x+2)^3 ?
The first derivative of y=(x^2+6x+2)^3 is 3(x^2+6x+2)^2(2x+6)