What is the derivative of 15x^2+2x-8 ?

The derivative of 15x^2+2x-8 is 30x+2

What is the first derivative of 15x^2+2x-8 ?

The first derivative of 15x^2+2x-8 is 30x+2

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\frac{d}{d x} (15 x^{2} + 2 x - 8)

30 x + 2

Solution steps

\frac{d}{d x} (15 x^{2} + 2 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (15 x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (8)

\frac{d}{d x} (15 x^{2}) = 30 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 30 x + 2 - 0

Simplify

= 30 x + 2

\int 4 sin (x + \frac{π}{4}) cos (x - \frac{π}{4}) d x

\frac{\partial}{\partial x} (\frac{x ( v - b )}{r ( x , v )})

\int \frac{sin ( x ) \cdot cos ( x )}{x} d x

\int \frac{1}{- 196.2 - 4 v ^{2}} d v

x \to \infty lim (\frac{4}{x})

What is the derivative of 15x^2+2x-8 ?
The derivative of 15x^2+2x-8 is 30x+2
What is the first derivative of 15x^2+2x-8 ?
The first derivative of 15x^2+2x-8 is 30x+2