What is the solution for (dx)/(dt)=x^2+1/25 ?

The solution for (dx)/(dt)=x^2+1/25 is x=(tan((t+c_{1})/5))/(5)

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(dx)/(dt)=x^2+1/25

\frac{d x}{d t} = x^{2} + \frac{1}{25}

x = \frac{tan ( \frac{t + c _{1}}{5} )}{5}

Solution steps

\frac{d x}{d t} = x^{2} + \frac{1}{25}

Solve separable ODE:

x = \frac{tan ( \frac{t + c _{1}}{5} )}{5}

x = \frac{tan ( \frac{t + c _{1}}{5} )}{5}

y = 6 x + 4 x - x^{2}, y = 2 x - 2

f (x) = x^{6} cos (x)

\frac{d}{d x} (x^{2} 10 x - 7)

f (x) = (x - 1) e^{x}

x \to 1 - lim (2^{\frac{1}{x - 2}})

What is the solution for (dx)/(dt)=x^2+1/25 ?
The solution for (dx)/(dt)=x^2+1/25 is x=(tan((t+c_{1})/5))/(5)