What is (\partial)/(\partial x)(ln(x+t^2)) ?

The answer to (\partial)/(\partial x)(ln(x+t^2)) is 1/(x+t^2)

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(\partial)/(\partial x)(ln(x+t^2))

\frac{\partial}{\partial x} (ln (x + t^{2}))

\frac{1}{x + t ^{2}}

Solution steps

\frac{\partial}{\partial x} (ln (x + t^{2}))

Treat

t

as a constant

Apply the chain rule:

\frac{1}{x + t ^{2}} \frac{\partial}{\partial x} (x + t^{2})

= \frac{1}{x + t ^{2}} \frac{\partial}{\partial x} (x + t^{2})

\frac{\partial}{\partial x} (x + t^{2}) = 1

= \frac{1}{x + t ^{2}} \cdot 1

Simplify

= \frac{1}{x + t ^{2}}

x^{2} - 10 x + 4

\frac{\partial}{\partial y} (\frac{1}{x + 2 y})

\int_{- 2}^{- 1} x f (x^{2} + 1) d x

f (x) = \frac{x}{( x - 1 ) ^{2}}

\frac{d}{d t} (ln (2 t))

What is (\partial)/(\partial x)(ln(x+t^2)) ?
The answer to (\partial)/(\partial x)(ln(x+t^2)) is 1/(x+t^2)