What is the first derivative of e^x+2 ?

The first derivative of e^x+2 is e^x

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derivative of e^x+2

\frac{d}{d x} (e^{x} + 2)

e^{x}

Solution steps

\frac{d}{d x} (e^{x} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (2)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2) = 0

= e^{x} + 0

Simplify

= e^{x}

y = ln (5 x - 2)

x \to 1 lim (- \frac{2 x}{x - 1})

\int 6 e^{6 x} d x

\frac{\partial}{\partial x} (sin (x + y))

x \to + (- 3) + lim (8 x + 5)