What is the first derivative of e^x+2 ?

The first derivative of e^x+2 is e^x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of e^x+2

\frac{d}{d x} (e^{x} + 2)

e^{x}

Solution steps

\frac{d}{d x} (e^{x} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) + \frac{d}{d x} (2)

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2) = 0

= e^{x} + 0

Simplify

= e^{x}

\int 6 e^{6 x} d x

x \to + (- 3) + lim (8 x + 5)

d er i v a t i v e f (x) = x^{l n (x)}

\frac{d}{d x} ((\frac{x - 2}{x - π})^{- 3})

\frac{\partial}{\partial x} (e^{- x^{2} + y^{2}})