What is the (x^2-2x-2sin(x-2))^' ?

The (x^2-2x-2sin(x-2))^' is 2x-2-2cos(x-2)

What is the first (x^2-2x-2sin(x-2))^' ?

The first (x^2-2x-2sin(x-2))^' is 2x-2-2cos(x-2)

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(x^{2} - 2 x - 2 sin (x - 2))^{^{'}}

2 x - 2 - 2 cos (x - 2)

Solution steps

(x^{2} - 2 x - 2 sin (x - 2))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (x^{2})^{^{'}} - (2 x)^{^{'}} - (2 sin (x - 2))^{^{'}}

(x^{2})^{'} = 2 x

(2 x)^{'} = 2

(2 sin (x - 2))^{'} = 2 cos (x - 2)

= 2 x - 2 - 2 cos (x - 2)

x \to 2 lim (4 ln (2))

n = 1 \sum \infty \frac{n !}{n !}

\int x cos (n x π) d x

\int \frac{1}{9 e ^{- 8 x} + e ^{8 x}} d x

f (x) = x^{2} x - 5 x

What is the (x^2-2x-2sin(x-2))^' ?
The (x^2-2x-2sin(x-2))^' is 2x-2-2cos(x-2)
What is the first (x^2-2x-2sin(x-2))^' ?
The first (x^2-2x-2sin(x-2))^' is 2x-2-2cos(x-2)