y^'=1+(y/x)

Lösung

y^{^{'}} = 1 + (\frac{y}{x})

y = ln (x) x + c_{1} x

Schritte zur Lösung

y^{'} (x) = 1 + (\frac{y}{x})

Solve linear ODE:

y = ln (x) x + c_{1} x

y = ln (x) x + c_{1} x

d er i v a t i v e f (x) = 1 + x^{256} - 1

\frac{d}{d x} (2 x 36 - x^{2})

\frac{\partial}{\partial y} (x^{2} y - x - x y^{2} + y)

\frac{d}{d x} (1 8^{x})

\frac{\partial}{\partial x} (ln (x^{3} y + 2 z))