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Popular >

y^'=1+(y/x)

Solution

y^{^{'}} = 1 + (\frac{y}{x})

Solution

y = ln (x) x + c_{1} x

Solution steps

y^{'} (x) = 1 + (\frac{y}{x})

Solve linear ODE:

y = ln (x) x + c_{1} x

y = ln (x) x + c_{1} x

Popular Examples

derivative of f(x)=sqrt(1+x^{256)}-1 derivative of

f (x) = 1 + x^{256} - 1

derivative of 2xsqrt(36-x^2)

\frac{d}{d x} (2 x 36 - x^{2})

xy^'+3y^'-(x+3)sin(x)+y=0

x y^{^{'}} + 3 y^{^{'}} - (x + 3) sin (x) + y = 0

(\partial)/(\partial y)(x^2y-x-xy^2+y)

\frac{\partial}{\partial y} (x^{2} y - x - x y^{2} + y)

derivative of 18^x

\frac{d}{d x} (1 8^{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'=1+(y/x) ?
The solution for y^'=1+(y/x) is y=ln(x)x+c_{1}x