What is the derivative of 3x^2-x+12 ?

The derivative of 3x^2-x+12 is 6x-1

What is the first derivative of 3x^2-x+12 ?

The first derivative of 3x^2-x+12 is 6x-1

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\frac{d}{d x} (3 x^{2} - x + 12)

6 x - 1

Solution steps

\frac{d}{d x} (3 x^{2} - x + 12)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (12)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d x}{d x} = 1

\frac{d}{d x} (12) = 0

= 6 x - 1 + 0

Simplify

= 6 x - 1

\int_{0}^{7} \frac{8 x}{( x - 8 ) ^{2}} d x

\int t^{\frac{1}{2}} d t

y = arctan (x^{2})

\int_{- \infty}^{- 1} e^{- 14 t} d t

\int 6 x^{2} - 5 d x

What is the derivative of 3x^2-x+12 ?
The derivative of 3x^2-x+12 is 6x-1
What is the first derivative of 3x^2-x+12 ?
The first derivative of 3x^2-x+12 is 6x-1