What is area y=0,y=x^3+8,[-3,-1] ?

The answer to area y=0,y=x^3+8,[-3,-1] is 25/2

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area y=0,y=x^3+8,[-3,-1]

area

y = 0, y = x^{3} + 8, [- 3, - 1]

\frac{25}{2}

Decimal Notation

12.5

Solution steps

Apply the area formula:

\int_{- 3}^{- 1} x^{3} + 8 d x

Solve

\int_{- 3}^{- 1} x^{3} + 8 d x : \frac{25}{2}

The area is:

= \frac{25}{2}

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What is area y=0,y=x^3+8,[-3,-1] ?
The answer to area y=0,y=x^3+8,[-3,-1] is 25/2