What is the derivative of x^2-x-ln(x) ?

The derivative of x^2-x-ln(x) is 2x-1-1/x

What is the first derivative of x^2-x-ln(x) ?

The first derivative of x^2-x-ln(x) is 2x-1-1/x

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\frac{d}{d x} (x^{2} - x - ln (x))

2 x - 1 - \frac{1}{x}

Solution steps

\frac{d}{d x} (x^{2} - x - ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d x}{d x} - \frac{d}{d x} (ln (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 2 x - 1 - \frac{1}{x}

\int_{- 1}^{2} (8 - x^{2}) d x

\frac{\partial}{\partial x} ((5 x + 9 y)^{10})

\frac{d}{d x} (3 cos (4 x))

\frac{\partial}{\partial t} (4 e^{s i n (x + 3 c t)})

\int_{0}^{4} π (x - 1)^{2} d x

What is the derivative of x^2-x-ln(x) ?
The derivative of x^2-x-ln(x) is 2x-1-1/x
What is the first derivative of x^2-x-ln(x) ?
The first derivative of x^2-x-ln(x) is 2x-1-1/x