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Popular >

y^'+y=e^x,y(0)=6

Solution

y^{^{'}} + y = e^{x}, y (0) = 6

Solution

y = \frac{e ^{x}}{2} + \frac{11}{2 e ^{x}}

Solution steps

y^{'} (x) + y = e^{x}

Solve linear ODE:

y = \frac{e ^{x}}{2} + \frac{11}{2 e ^{x}}

y = \frac{e ^{x}}{2} + \frac{11}{2 e ^{x}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+y=e^x,y(0)=6 ?
The solution for y^'+y=e^x,y(0)=6 is y=(e^x)/2+(11)/(2e^x)