What is the integral of x(2x^2+1)^{3/2} ?

The integral of x(2x^2+1)^{3/2} is 1/5 x^2(2x^2+1)^{3/2}+1/10 (2x^2+1)^{3/2}+C

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integral of x(2x^2+1)^{3/2}

\int x (2 x^{2} + 1)^{\frac{3}{2}} d x

\frac{1}{5} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} + \frac{1}{10} (2 x^{2} + 1)^{\frac{3}{2}} + C

Solution steps

\int x (2 x^{2} + 1)^{\frac{3}{2}} d x

Apply Integration By Parts

: \frac{1}{2} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} - \int 3 x^{3} (2 x^{2} + 1)^{\frac{1}{2}} d x

= \frac{1}{2} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} - \int 3 x^{3} (2 x^{2} + 1)^{\frac{1}{2}} d x

\int 3 x^{3} (2 x^{2} + 1)^{\frac{1}{2}} d x = \frac{1}{10} (3 x^{2} - 1) (2 x^{2} + 1)^{\frac{3}{2}}

= \frac{1}{2} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} - \frac{1}{10} (3 x^{2} - 1) (2 x^{2} + 1)^{\frac{3}{2}}

Simplify

\frac{1}{2} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} - \frac{1}{10} (3 x^{2} - 1) (2 x^{2} + 1)^{\frac{3}{2}} : \frac{1}{5} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} + \frac{1}{10} (2 x^{2} + 1)^{\frac{3}{2}}

= \frac{1}{5} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} + \frac{1}{10} (2 x^{2} + 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{5} x^{2} (2 x^{2} + 1)^{\frac{3}{2}} + \frac{1}{10} (2 x^{2} + 1)^{\frac{3}{2}} + C

\frac{\partial}{\partial x} (x^{2} \cdot cos (x y))

y = 10 x^{2}, y^{2} = \frac{1}{10} x

x \to 3 - lim (\frac{1}{( x - 3 ) ^{2}})

\int \frac{1}{2 x 16 x ^{2} - 8} d x

\int 4^{3 x} d x

What is the integral of x(2x^2+1)^{3/2} ?
The integral of x(2x^2+1)^{3/2} is 1/5 x^2(2x^2+1)^{3/2}+1/10 (2x^2+1)^{3/2}+C