What is the derivative of 3x^{1/4} ?

The derivative of 3x^{1/4} is 3/(4x^{3/4)}

What is the first derivative of 3x^{1/4} ?

The first derivative of 3x^{1/4} is 3/(4x^{3/4)}

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\frac{d}{d x} (3 x^{\frac{1}{4}})

\frac{3}{4 x ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (3 x^{\frac{1}{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

3 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : \frac{3}{4 x ^{\frac{3}{4}}}

= \frac{3}{4 x ^{\frac{3}{4}}}

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 72 x + 3)

y = ln (sec (x) + tan (x))

\frac{d}{d x} ((2 x - 45) (x^{2} + 162))

\frac{d}{d x} (sin^{3} (cos^{2} (e^{x^{2} + 1})))

What is the derivative of 3x^{1/4} ?
The derivative of 3x^{1/4} is 3/(4x^{3/4)}
What is the first derivative of 3x^{1/4} ?
The first derivative of 3x^{1/4} is 3/(4x^{3/4)}