What is the derivative of y=(2x)/(5-cot(x)) ?

The derivative of y=(2x)/(5-cot(x)) is (2(5-cot(x)-xcsc^2(x)))/((5-cot(x))^2)

What is the first derivative of y=(2x)/(5-cot(x)) ?

The first derivative of y=(2x)/(5-cot(x)) is (2(5-cot(x)-xcsc^2(x)))/((5-cot(x))^2)

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derivative of

y = \frac{2 x}{5 - cot ( x )}

\frac{2 ( 5 - cot ( x ) - x csc ^{2} ( x ) )}{( 5 - cot ( x ) ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2 x}{5 - cot ( x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{5 - cot ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} ( 5 - cot ( x ) ) - \frac{d}{d x} ( 5 - cot ( x ) ) x}{( 5 - cot ( x ) ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (5 - cot (x)) = csc^{2} (x)

= 2 \cdot \frac{1 \cdot ( 5 - cot ( x ) ) - csc ^{2} ( x ) x}{( 5 - cot ( x ) ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot ( 5 - cot ( x ) ) - csc ^{2} ( x ) x}{( 5 - cot ( x ) ) ^{2}} : \frac{2 ( 5 - cot ( x ) - x csc ^{2} ( x ) )}{( 5 - cot ( x ) ) ^{2}}

= \frac{2 ( 5 - cot ( x ) - x csc ^{2} ( x ) )}{( 5 - cot ( x ) ) ^{2}}

\frac{\partial}{\partial y} (4 x^{2} + 3 y^{4})

x \to 0 lim (\frac{tan ( x ) - x}{x})

\int cot^{2} (3 x) d x

\int (1 + x)^{3} d x

\int_{0}^{5} \frac{5 - x}{5} d x

What is the derivative of y=(2x)/(5-cot(x)) ?
The derivative of y=(2x)/(5-cot(x)) is (2(5-cot(x)-xcsc^2(x)))/((5-cot(x))^2)
What is the first derivative of y=(2x)/(5-cot(x)) ?
The first derivative of y=(2x)/(5-cot(x)) is (2(5-cot(x)-xcsc^2(x)))/((5-cot(x))^2)