What is the tangent of sqrt(x),\at x=144 ?

The tangent of sqrt(x),\at x=144 is y= 1/24 x+6

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tangent of sqrt(x),\at x=144

tangent of

x, at x = 144

y = \frac{1}{24} x + 6

Solution steps

Find the tangent point:

(144, 12)

Find the slope of

y = x : \frac{d y}{d x} = \frac{1}{2 x}

Compute the slope of

y = x

x = 144 : m = \frac{1}{24}

Find the line with slope m=

\frac{1}{24}

and passing through

(144, 12) : y = \frac{1}{24} x + 6

y = \frac{1}{24} x + 6

\int \frac{x ^{3} + x ^{2} - x ^{5}}{x ^{6}} d x

\frac{d}{d x} (\frac{1}{4} (x^{4} + 8))

g (x) = 3 x^{4} - 140 x^{3}

\int \frac{1}{t} d t

\frac{d}{d x} (4 x^{3} y^{- 2})

What is the tangent of sqrt(x),\at x=144 ?
The tangent of sqrt(x),\at x=144 is y= 1/24 x+6