What is the solution for y^{''}-y^'-2y=-6t+6t^2 ?

The solution for y^{''}-y^'-2y=-6t+6t^2 is y=c_{1}e^{2t}+c_{2}e^{-t}-3t^2+6t-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y^'-2y=-6t+6t^2

y^{^{''}} - y^{^{'}} - 2 y = - 6 t + 6 t^{2}

y = c_{1} e^{2 t} + c_{2} e^{- t} - 3 t^{2} + 6 t - 6

Solution steps

y^{''} (t) - y^{'} (t) - 2 y = - 6 t + 6 t^{2}

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- t} - 3 t^{2} + 6 t - 6

y = c_{1} e^{2 t} + c_{2} e^{- t} - 3 t^{2} + 6 t - 6

\int \frac{1}{2 x ^{3} + x} d x

\frac{\partial}{\partial x} ((0.5 x^{2} + 0.5 y^{2})^{\frac{1}{2}})

\int_{0}^{\frac{π}{2}} cos^{5} (1) d x

y^{^{''}} - 4 y^{^{'}} + 4 y = t^{- 6} e^{2 t}

\frac{\partial}{\partial y} (x e^{x^{2} y})

What is the solution for y^{''}-y^'-2y=-6t+6t^2 ?
The solution for y^{''}-y^'-2y=-6t+6t^2 is y=c_{1}e^{2t}+c_{2}e^{-t}-3t^2+6t-6