What is the limit as x approaches 2 of sqrt(2x) ?

The limit as x approaches 2 of sqrt(2x) is 2

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limit as x approaches 2 of sqrt(2x)

x \to 2 lim (2 x)

2

Solution steps

x \to 2 lim (2 x)

Plug in the value

x = 2

= 2 \cdot 2

Simplify

2 \cdot 2 : 2

= 2

y^{^{''}} - 4 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 5

y^{^{''}} - y = e^{t}

\int \frac{24 q}{4 q ^{2} + 7} d q

\frac{\partial}{\partial x} (2 x^{2} y + 3 x y^{3})

f^{^{'}} (x) = \frac{( 5 x + 1 )}{5 x}

What is the limit as x approaches 2 of sqrt(2x) ?
The limit as x approaches 2 of sqrt(2x) is 2