What is the derivative of 1-2x-3x^2 ?

The derivative of 1-2x-3x^2 is -6x-2

What is the first derivative of 1-2x-3x^2 ?

The first derivative of 1-2x-3x^2 is -6x-2

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\frac{d}{d x} (1 - 2 x - 3 x^{2})

- 6 x - 2

Solution steps

\frac{d}{d x} (1 - 2 x - 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (2 x) - \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 - 2 - 6 x

Simplify

= - 6 x - 2

\int \frac{1}{x ^{2} ( 9 + x ^{2} )} d x

\int \frac{5}{x ^{2} x ^{2} + 4} d x

\int_{16}^{x} 1 + 9 t d t

\frac{d y}{d x} = - 5 sin (4 x)

What is the derivative of 1-2x-3x^2 ?
The derivative of 1-2x-3x^2 is -6x-2
What is the first derivative of 1-2x-3x^2 ?
The first derivative of 1-2x-3x^2 is -6x-2