What is the limit as x approaches 3+of (3-x)/(x^2-9) ?

The limit as x approaches 3+of (3-x)/(x^2-9) is -1/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 3+of (3-x)/(x^2-9)

x \to 3 + lim (\frac{3 - x}{x ^{2} - 9})

- \frac{1}{6}

Decimal Notation

- 0.16666 \dots

Solution steps

x \to 3 + lim (\frac{3 - x}{x ^{2} - 9})

Simplify

\frac{3 - x}{x ^{2} - 9} : - \frac{1}{x + 3}

= x \to 3 + lim (- \frac{1}{x + 3})

Plug in the value

x = 3

= - \frac{1}{3 + 3}

Simplify

= - \frac{1}{6}

t \to 1 lim (\frac{t ^{2} - t}{t - 1})

\frac{d ^{2}}{d x ^{2}} f (x) = x^{3} + 3 x^{2} - 2 x + 1

\frac{\partial}{\partial x} (2 x y e^{x z})

x

\frac{d}{d x} (\frac{4}{3} sin (x))

What is the limit as x approaches 3+of (3-x)/(x^2-9) ?
The limit as x approaches 3+of (3-x)/(x^2-9) is -1/6