What is the integral of (x^2+4x+1)/(x^3+x) ?

The integral of (x^2+4x+1)/(x^3+x) is ln|x|+4arctan(x)+C

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integral of (x^2+4x+1)/(x^3+x)

\int \frac{x ^{2} + 4 x + 1}{x ^{3} + x} d x

ln ∣ x ∣ + 4 arctan (x) + C

Solution steps

\int \frac{x ^{2} + 4 x + 1}{x ^{3} + x} d x

Take the partial fraction of

\frac{x ^{2} + 4 x + 1}{x ^{3} + x} : \frac{1}{x} + \frac{4}{x ^{2} + 1}

= \int \frac{1}{x} + \frac{4}{x ^{2} + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x} d x + \int \frac{4}{x ^{2} + 1} d x

\int \frac{1}{x} d x = ln ∣ x ∣

\int \frac{4}{x ^{2} + 1} d x = 4 arctan (x)

= ln ∣ x ∣ + 4 arctan (x)

Add a constant to the solution

= ln ∣ x ∣ + 4 arctan (x) + C

\frac{d}{d x} (\frac{( x ^{2} - 1 )}{x ^{2}})

\int - sin (x) cos^{2} (x) d x

\frac{( 1 - 4 x )}{1 + 4 x}

3 x d y + 4 y d x = x^{2} y^{2} d x

\frac{d}{d x} (ln (18 x))

What is the integral of (x^2+4x+1)/(x^3+x) ?
The integral of (x^2+4x+1)/(x^3+x) is ln|x|+4arctan(x)+C