derivative 8e^x+2/(\sqrt[3]{x)}

解答

导数

8 e^{x} + \frac{2}{3 x}

8 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

求解步骤

\frac{d}{d x} (8 e^{x} + \frac{2}{3 x})

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 e^{x}) + \frac{d}{d x} (\frac{2}{3 x})

\frac{d}{d x} (8 e^{x}) = 8 e^{x}

\frac{d}{d x} (\frac{2}{3 x}) = - \frac{2}{3 x ^{\frac{4}{3}}}

= 8 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

t an g e n t f (x) = \frac{1}{x ^{2}}, (2, \frac{1}{4})

\frac{d}{d x} (x^{3} + x + 1)

n = 1 \sum \infty n^{2} \cdot e^{- n}

\int_{1}^{2} 7 4 x^{2} - 3 d x

\int x^{- 10} d x