What is (\partial)/(\partial x)(t^6e^{-x}) ?

The answer to (\partial)/(\partial x)(t^6e^{-x}) is -e^{-x}t^6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(t^6e^{-x})

\frac{\partial}{\partial x} (t^{6} e^{- x})

- e^{- x} t^{6}

Solution steps

\frac{\partial}{\partial x} (t^{6} e^{- x})

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= t^{6} \frac{\partial}{\partial x} (e^{- x})

Apply the chain rule:

e^{- x} \frac{\partial}{\partial x} (- x)

= e^{- x} \frac{\partial}{\partial x} (- x)

\frac{\partial}{\partial x} (- x) = - 1

= t^{6} e^{- x} (- 1)

Simplify

= - e^{- x} t^{6}

y^{^{''}} + 4 y = 4 x

\int x^{2} + 5 x + 1 d x

\frac{d}{d x} f (x) = (x - 1 - x^{2})^{2}

\frac{d}{d x} (12 cos (2 x + \frac{π}{6}))

\frac{d y}{d x} - 2 y = e^{x}

What is (\partial)/(\partial x)(t^6e^{-x}) ?
The answer to (\partial)/(\partial x)(t^6e^{-x}) is -e^{-x}t^6