What is (\partial)/(\partial x)(t^2e^x+3x^2) ?

The answer to (\partial)/(\partial x)(t^2e^x+3x^2) is t^2e^x+6x

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(\partial)/(\partial x)(t^2e^x+3x^2)

\frac{\partial}{\partial x} (t^{2} e^{x} + 3 x^{2})

t^{2} e^{x} + 6 x

Solution steps

\frac{\partial}{\partial x} (t^{2} e^{x} + 3 x^{2})

Treat

t

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (t^{2} e^{x}) + \frac{\partial}{\partial x} (3 x^{2})

\frac{\partial}{\partial x} (t^{2} e^{x}) = t^{2} e^{x}

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

= t^{2} e^{x} + 6 x

\int_{2}^{7} 3 d x

x \to 2 lim (x^{2} + x - 6)

\int_{0}^{π} sin^{3} (x) d x

\frac{( 2 s + 1 )}{s ( 2 s + 10 )}

\frac{d}{d x} ((- x^{2} - 4)^{2})

What is (\partial)/(\partial x)(t^2e^x+3x^2) ?
The answer to (\partial)/(\partial x)(t^2e^x+3x^2) is t^2e^x+6x