What is the derivative of 2x^3+x ?

The derivative of 2x^3+x is 6x^2+1

What is the first derivative of 2x^3+x ?

The first derivative of 2x^3+x is 6x^2+1

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\frac{d}{d x} (2 x^{3} + x)

6 x^{2} + 1

Solution steps

\frac{d}{d x} (2 x^{3} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d x}{d x}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d x}{d x} = 1

= 6 x^{2} + 1

\frac{\partial}{\partial x} (y^{2} e^{2 x})

\frac{d}{d x} (e^{x^{2} - 4} + 2 x + 9)

\frac{d}{d x} (tan^{4} (cot (3 x^{4} + 5 x)))

x \frac{d y}{d x} = x^{3} + 24 x^{3} y

\int (2 cos (x)) d x

What is the derivative of 2x^3+x ?
The derivative of 2x^3+x is 6x^2+1
What is the first derivative of 2x^3+x ?
The first derivative of 2x^3+x is 6x^2+1