en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(x+1)*(y+1)

Solution

y^{^{'}} = (x + 1) \cdot (y + 1)

Solution

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

Solution steps

y^{'} (x) = (x + 1) \cdot (y + 1)

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

Popular Examples

limit as x approaches pi of tan(5/6 x)

x \to π lim (tan (\frac{5}{6} x))

(x^2-1)(dy)/(dx)=x(y-1)

(x^{2} - 1) \frac{d y}{d x} = x (y - 1)

derivative of 7x^2+1

\frac{d}{d x} (7 x^{2} + 1)

integral of 1/(2+x-x^2)

\int \frac{1}{2 + x - x ^{2}} d x

integral of (4sin^3(sqrt(x)))/(sqrt(x))

\int \frac{4 sin ^{3} ( x )}{x} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x+1)*(y+1) ?
The solution for y^'=(x+1)*(y+1) is y=e^{(x^2)/2+x+c_{1}}-1