What is the sum from n=0 to infinity of 5/(10^{3n)} ?

The sum from n=0 to infinity of 5/(10^{3n)} is converges

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sum from n=0 to infinity of 5/(10^{3n)}

n = 0 \sum \infty \frac{5}{1 0 ^{3 n}}

converges

Solution steps

n = 0 \sum \infty \frac{5}{1 0 ^{3 n}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot n = 0 \sum \infty \frac{1}{1 0 ^{3 n}}

Apply Series Ratio Test:

converges

= 5 converges

= converges

\int - 6 x + 5 d x

\int e^{- a x} x^{2} d x

f (x) = 3 - e^{- 3 x}, at x = - ln (2)

\frac{\partial}{\partial x} (20 + 5 sin (x) cos (x - y))

\int \frac{e ^{2 x}}{x} d x

What is the sum from n=0 to infinity of 5/(10^{3n)} ?
The sum from n=0 to infinity of 5/(10^{3n)} is converges