What is the derivative of 3/(x^2-1) ?

The derivative of 3/(x^2-1) is -(6x)/((x^2-1)^2)

What is the first derivative of 3/(x^2-1) ?

The first derivative of 3/(x^2-1) is -(6x)/((x^2-1)^2)

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\frac{d}{d x} (\frac{3}{x ^{2} - 1})

- \frac{6 x}{( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{2} - 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} (\frac{1}{x ^{2} - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d x} ((x^{2} - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x ^{2} - 1 ) ^{2}} \frac{d}{d x} (x^{2} - 1)

= - \frac{1}{( x ^{2} - 1 ) ^{2}} \frac{d}{d x} (x^{2} - 1)

\frac{d}{d x} (x^{2} - 1) = 2 x

= 3 (- \frac{1}{( x ^{2} - 1 ) ^{2}} \cdot 2 x)

Simplify

3 (- \frac{1}{( x ^{2} - 1 ) ^{2}} \cdot 2 x) : - \frac{6 x}{( x ^{2} - 1 ) ^{2}}

= - \frac{6 x}{( x ^{2} - 1 ) ^{2}}

\int sin (3 x) sin (7 x) d x

\frac{d}{d x} (- x^{\frac{2}{3}})

x \to 1 lim (\frac{x ^{3} + 1}{x + 1})

y^{^{'}} = \frac{x ^{2} + 3 x + 2}{y - 2}

\frac{d}{d x} (arctan^{2} (x^{3}))

What is the derivative of 3/(x^2-1) ?
The derivative of 3/(x^2-1) is -(6x)/((x^2-1)^2)
What is the first derivative of 3/(x^2-1) ?
The first derivative of 3/(x^2-1) is -(6x)/((x^2-1)^2)