What is the integral of (sin(x/2)) ?

The integral of (sin(x/2)) is -2cos(x/2)+C

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integral of (sin(x/2))

\int (sin (\frac{x}{2})) d x

- 2 cos (\frac{x}{2}) + C

Solution steps

\int sin (\frac{x}{2}) d x

Apply u-substitution

: \int sin (u) \cdot 2 d u

= \int sin (u) \cdot 2 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= 2 (- cos (u))

Substitute back

u = \frac{x}{2}

= 2 (- cos (\frac{x}{2}))

Simplify

= - 2 cos (\frac{x}{2})

Add a constant to the solution

= - 2 cos (\frac{x}{2}) + C

sin (x), 3 x, \frac{π}{2}, π

x \to 1 - lim (\frac{x}{x ^{2} - 1})

\frac{d}{d x} ((x + 2)^{- 2})

f (x) = \frac{x}{e ^{x}}

y = 8 x - x^{2} (1.7)