What is the solution for (dy)/(dt)=ky^2,y(0)=47 ?

The solution for (dy)/(dt)=ky^2,y(0)=47 is y=-(47)/(47kt-1)

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(dy)/(dt)=ky^2,y(0)=47

\frac{d y}{d t} = k y^{2}, y (0) = 47

y = - \frac{47}{47 k t - 1}

Solution steps

\frac{d y}{d t} = k y (t)^{2}

Solve separable ODE:

y = - \frac{47}{47 k t - 1}

y = - \frac{47}{47 k t - 1}

\frac{\partial}{\partial x} ((x^{2} + y^{2})^{\frac{3}{2}})

\frac{\partial}{\partial x} (x^{3} - y^{3} + 2 x y)

x \to 2 lim (3 x - 6)

\frac{\partial}{\partial x} (e (y^{2}))

f (x) = sin^{3} (2 x)

What is the solution for (dy)/(dt)=ky^2,y(0)=47 ?
The solution for (dy)/(dt)=ky^2,y(0)=47 is y=-(47)/(47kt-1)