What is the solution for cos^2(x)sin(x)y^'+cos^3(x)y=1 ?

The solution for cos^2(x)sin(x)y^'+cos^3(x)y=1 is y=(tan(x))/(sin(x))+(c_{1})/(sin(x))

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cos^2(x)sin(x)y^'+cos^3(x)y=1

cos^{2} (x) sin (x) y^{^{'}} + cos^{3} (x) y = 1

y = \frac{tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

Solution steps

cos^{2} (x) sin (x) y^{'} (x) + cos^{3} (x) y = 1

Solve linear ODE:

y = \frac{tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

y = \frac{tan ( x )}{sin ( x )} + \frac{c _{1}}{sin ( x )}

2 t \frac{d y}{d t} = 8 y

\frac{\partial}{\partial x} (x e^{6 y})

\frac{\partial}{\partial x} (\frac{x ^{\frac{3}{2}}}{3})

\frac{\partial}{\partial y} (2 x^{2} y + 3 x y^{3})

\int_{0}^{8} x^{3} x^{2} + 64 d x

What is the solution for cos^2(x)sin(x)y^'+cos^3(x)y=1 ?
The solution for cos^2(x)sin(x)y^'+cos^3(x)y=1 is y=(tan(x))/(sin(x))+(c_{1})/(sin(x))