What is (\partial)/(\partial x)(sqrt(26-x^2-y^2)) ?

The answer to (\partial)/(\partial x)(sqrt(26-x^2-y^2)) is -x/(sqrt(26-x^2-y^2))

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(\partial)/(\partial x)(sqrt(26-x^2-y^2))

\frac{\partial}{\partial x} (26 - x^{2} - y^{2})

- \frac{x}{26 - x ^{2} - y ^{2}}

Solution steps

\frac{\partial}{\partial x} (26 - x^{2} - y^{2})

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 26 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (26 - x^{2} - y^{2})

= \frac{1}{2 26 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (26 - x^{2} - y^{2})

\frac{\partial}{\partial x} (26 - x^{2} - y^{2}) = - 2 x

= \frac{1}{2 26 - x ^{2} - y ^{2}} (- 2 x)

Simplify

\frac{1}{2 26 - x ^{2} - y ^{2}} (- 2 x) : - \frac{x}{26 - x ^{2} - y ^{2}}

= - \frac{x}{26 - x ^{2} - y ^{2}}

\frac{d}{d x} (sec (x^{2} - 1))

(t - 1)^{4}

\frac{d}{d x} (\frac{2 x ^{4} + 5}{4 - 4 x})

\frac{\partial}{\partial x} (25 - x^{2})

\frac{d y}{d x} + \frac{1}{x + 8} y = x^{- 2}

What is (\partial)/(\partial x)(sqrt(26-x^2-y^2)) ?
The answer to (\partial)/(\partial x)(sqrt(26-x^2-y^2)) is -x/(sqrt(26-x^2-y^2))