What is laplacetransform t+2 ?

The answer to laplacetransform t+2 is 1/(s^2)+2/s

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laplacetransform t+2

laplace transform

t + 2

\frac{1}{s ^{2}} + \frac{2}{s}

Solution steps

L {t + 2}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} + L {2}

L {t} : \frac{1}{s ^{2}}

L {2} : \frac{2}{s}

= \frac{1}{s ^{2}} + \frac{2}{s}

\int - \frac{26}{x ^{27}} d x

x \to \infty lim (2^{2})

\int e^{\frac{x}{4}} d x

y^{^{'}} - 2 y = e^{3 x}

n \to 1 lim (\frac{( - \frac{1}{5} ) ^{n}}{n})

What is laplacetransform t+2 ?
The answer to laplacetransform t+2 is 1/(s^2)+2/s